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=> x^4/3*4-x^3/3+7/3x
=>F(x)= x^4/12-4x^3/12+28/12x
$$\int_{-1}^{2} f (x)\,dx = F(2)-F(-1) = 2^4/12-4*2^3/12+28/12*2-(-1^4/12-4*-1^3/12+28/12*-1)$$
=4/3-8/3+14/3-(1/12+4/12-7/3
=4/3-8/3+14/3-1/12-4/12+7/3
=16/12-32/12+56/12-1/12-4/12+28/12
=63/12
=5,25
